How to solve your problem:
(and as a former physics student, I understand!)
Set the velocity equal to 70.
70=80(1-e^.2t)
Next, divide both sides by 80
7/8 = 1-e^.2t
Add e^.2 t to both sides
7/8 + e^.2t= 1
subtract 7/8 from both sides
e^.2t=1/8
Take the ln of both sides
.2t= ln(1/8)
Divide by .2
t= ln (1/8)/.2
I hope this helps!
2007-01-16 15:48:43
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answer #1
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answered by Madama Butterfly 4
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set your equation equal to 70.
80 (1 - e^0.2t) = 70
As there's an e in your problem and no need to derive or integrate, I'd divide both sides by 80, subtract 1 from both sides, take the natural log (ln) of both sides to eliminate the e, and solve.
-e^0.2t = 70/80 - 1
-e^0.2t = -10/80
e^0.2t = 1/8
ln (e^0.2t) = ln (1/8)
0.2t = ln 1 - ln 8
0.2t = -ln 8
t = -5 ln 8
Does that make sense? The time seems to be coming out negative, which I can't understand, but I can't find an error in the problem either.
2007-01-16 15:49:58
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answer #2
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answered by Shanny 2
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This is plug and play!
70 = 80(1 - e^(-0.2t)) then untangle, divide both sides by 80,
So (7/8) = 1 - e^(-0.2t)subtract 1 from both sides, and multiply both sides by -1 to remove negative signs
(1/8)= e^ (-0.2t)
and take the natural log of both sides
-2.079= -0.2t
then divide both sides by the coefficient of t and voila! 10.397
2007-01-16 15:59:54
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answer #3
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answered by lynn y 3
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1/4 of 28 is 7 - 7 go to the guidance office 28-7 is 21 - 21 remain - 1/3 of 21 is 7 - 7 go to the nurse 21-7 is 14 - 14 are left - 1/2 of 14 is 7 - 7 fo to the library 14-7 is 7 - 7 remain in the classroom
2016-05-23 23:02:05
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answer #4
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answered by Anonymous
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v(t)= 80(1-e^-0.2t) =70
1-e^-0.2t=7/8
e^-0.2t=1/8
-0.2t=ln 1/8
0.2t=ln 8
t=5 ln 8=10.40 sec
2007-01-16 17:13:42
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answer #5
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answered by yupchagee 7
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Shanny, you are smart but a bit of an idiot. The time is not negative. You have added MINUS ONE to both sides. So, the answer is MINUS E = MINUS T. If you multiply both sides by MINUS ONE, both sides become positive. And I teach English, not math! SHEEEEESH!
2007-01-16 15:59:24
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answer #6
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answered by Anpadh 6
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