x² +5x+4 = 0
delta = 5² - 4.1.4
delta = 25 - 16 = 9
x = (-5 +/-\/9) : 2
x' = (-5 + 3) :2 = -1
x" = (-5 -3) : 2 = -4
For y = 0; x = -1 or x = -4.
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2007-01-16 15:15:40
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answer #1
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answered by aeiou 7
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To factor, look for two numbers which multiply to give 4 and add to 5.
Only possibilities are 1*4 and 2*2, obviously 1*4 is the pair you want, so it's
y = (x+1)(x+4).
The graph crosses the x axis where y = 0, so that gives us two places: where x+1 = 0 and so x = -1, and where x+4 = 0 and so x = -4.
Because the x^2 term has a positive coefficient (it's +1), the graph is concave upwards. (some people call it "smiley"). Its lowest point is halfway between -4 and -1, that is at
x = -2.5
Sub x = -2.5 and find y = -2.25.
Mark these three points (-4,0) (-2.5, -2.25) (-1,0) and draw a smooth parabola through them.
For good measure, notice that when x = 0 y =4, so make it cross the y axis at (0,4)
2007-01-16 15:13:27
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answer #2
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answered by Hy 7
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So you know you have 2 expressions (x+ )(x + ) the signs are both positive so you need two factors that multiply to give you 4 and that add up to 5 (4*1 =4, and 4+1 =5) so the factors become (x+4)(x+1) and your solutions are -4, -1
2007-01-16 15:18:30
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answer #3
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answered by lynn y 3
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y=(x+1)(x+4)
2007-01-16 15:17:52
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answer #4
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answered by Danielle S 3
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y=(x+5/2)^2-9/4
Move the graph of
y=x^2
9/4 Down & 5/2 Left!
2007-01-16 18:39:01
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answer #5
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answered by alaki 1
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x² +5x+4 = 0
delta = 5² - 4.1.4
delta = 25 - 16 = 9
x = (-5 +/-\/9) : 2
x' = (-5 + 3) :2 = -1
x" = (-5 -3) : 2 = -4
For y = 0; x = -1 or x = -4.
2007-01-16 19:17:34
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answer #6
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answered by Kinu Sharma 2
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Math major right here.... You cant sparkling up this question as you've it written. are you searching for the zeros of the equation? if so then using the quadratic equation you get (x-4)(x-a million)=0 and then x is 4 or a million..........................
2016-11-24 22:29:00
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answer #7
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answered by Anonymous
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y=(x+1)(x+4)
y=0
x=-1 and -4
2007-01-16 15:24:43
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answer #8
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answered by Anonymous
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dude, do your own hw.
2007-01-16 15:17:04
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answer #9
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answered by JJcD 4
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