water: 100 mL
C12 H22 O11: 45g
2007-01-16 15:08:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
water: 99mL
HC2H3O2: 1mL
2007-01-16 15:11:19 · update #1
how you do it and what is formula to use?
2007-01-16 15:18:55 · update #2
the mass no;
C=12 x 22=264
H=1x22=22
O=16x11=176
We can get the total mass no by adding them,
total=462.
the required percent can get as: 45 is divided by 462 and the result is multiplied with100.
2007-01-16 15:59:50 · answer #1 · answered by thetyee w 1 · 0⤊ 0⤋
45/145=.31
.31 X 100%= 31 % C12 H22 O11 by mass
2007-01-16 23:12:12 · answer #2 · answered by f0876and1_2 5 · 0⤊ 0⤋
You have 45 grams of sucrose and 100 grams of water. Your sucrose is 45 / 145 percent mass.
2007-01-16 23:12:07 · answer #3 · answered by reb1240 7 · 0⤊ 0⤋
With a calculator.
2007-01-16 23:10:50 · answer #4 · answered by Anonymous · 0⤊ 1⤋