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6 answers

(sqrt)45/(sqrt)32
=(sqrt) 9X5/(sqrt)16X2
=3(sqrt)5/4(sqrt)2
=3(sqrt)5X(sqrt)2/4(sqrt)2X(sqrt)2 [multiplying numerator and denominator by (sqrt)2
=3(sqrt)10/4X2
=(3/8) (sqrt)10 ans

2007-01-16 15:16:06 · answer #1 · answered by alpha 7 · 0 0

(45)^1/2 = 3 (5^1/2)
(32)^1/2 = 4 (2^1/2)

Dividing them, we get: [3 (5^1/2)] / [4 (2^1/2)].

The denominator contains an irrational number, so let's rationalize it. To do that, multiply both numerator and denominator by [4 (2^1/2)]. The result is:

[12 (10)^1/2 ] / 32, which we can reduce to (3/8)(10)^1/2. In words, the answer is three-eighths times the square root of 10.

2007-01-16 23:30:34 · answer #2 · answered by MathBioMajor 7 · 0 0

Factoring:
45|3
15|3
05|5
01
\/45 = 3\/5
32|2
16|2
08|2
04|2
02|2
01
\/32 = 4\/2
Division: 3\/5 over 4\/2
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2007-01-16 23:25:18 · answer #3 · answered by aeiou 7 · 0 0

3 root 5 divided by 4 root2

2007-01-16 23:14:10 · answer #4 · answered by cleareye328 2 · 0 0

rewrite as the (sqrt of 9 times 5) divided by the (sqrt of 2 times 16) so you can remove the perfect squares ( 9 and 16) and you have (3 times the sqrt of 5) divided by (4 times the sqrt of 2)

2007-01-16 23:13:29 · answer #5 · answered by lynn y 3 · 0 0

sqrt 45 / sqrt 32 = sqrt (45/32) = sqrt (3^2*5/2^5) = (3/2^2)sqrt(5/2)

= (3/4) sqrt(5/2)

Bozo

2007-01-16 23:10:42 · answer #6 · answered by bozo 4 · 0 0

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