(sqrt)45/(sqrt)32
=(sqrt) 9X5/(sqrt)16X2
=3(sqrt)5/4(sqrt)2
=3(sqrt)5X(sqrt)2/4(sqrt)2X(sqrt)2 [multiplying numerator and denominator by (sqrt)2
=3(sqrt)10/4X2
=(3/8) (sqrt)10 ans
2007-01-16 15:16:06
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answer #1
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answered by alpha 7
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(45)^1/2 = 3 (5^1/2)
(32)^1/2 = 4 (2^1/2)
Dividing them, we get: [3 (5^1/2)] / [4 (2^1/2)].
The denominator contains an irrational number, so let's rationalize it. To do that, multiply both numerator and denominator by [4 (2^1/2)]. The result is:
[12 (10)^1/2 ] / 32, which we can reduce to (3/8)(10)^1/2. In words, the answer is three-eighths times the square root of 10.
2007-01-16 23:30:34
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answer #2
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answered by MathBioMajor 7
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Factoring:
45|3
15|3
05|5
01
\/45 = 3\/5
32|2
16|2
08|2
04|2
02|2
01
\/32 = 4\/2
Division: 3\/5 over 4\/2
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2007-01-16 23:25:18
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answer #3
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answered by aeiou 7
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3 root 5 divided by 4 root2
2007-01-16 23:14:10
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answer #4
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answered by cleareye328 2
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rewrite as the (sqrt of 9 times 5) divided by the (sqrt of 2 times 16) so you can remove the perfect squares ( 9 and 16) and you have (3 times the sqrt of 5) divided by (4 times the sqrt of 2)
2007-01-16 23:13:29
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answer #5
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answered by lynn y 3
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sqrt 45 / sqrt 32 = sqrt (45/32) = sqrt (3^2*5/2^5) = (3/2^2)sqrt(5/2)
= (3/4) sqrt(5/2)
Bozo
2007-01-16 23:10:42
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answer #6
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answered by bozo 4
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