example...
y= (x+3)^2 +1 makes what in standard form?
2007-01-16 14:39:23 · 5 answers · asked by GivinTakinKnowin 2 in Science & Mathematics ➔ Mathematics
i think the standard form is 0 = ax^2+bx+c, not sure. multiple it out and put it in that form.
2007-01-16 14:45:17 · answer #1 · answered by Taras 2 · 0⤊ 0⤋
y = (x + 3)(x + 3) + 1
= x^2 + 6x + 9 + 1
y = x^2 + 6x + 10
so, to write this in standard form we will move all the terms to RHS
-x^2 + y - 6x - 10=0
2007-01-16 14:57:41 · answer #2 · answered by bochevik 2 · 0⤊ 0⤋
y= (x+3)(x+3) + 1< multiply the (x+3)'s
y=(x^2+6x+9)+1 and add like components
Y= x^2+6x+10
2007-01-16 14:46:58 · answer #3 · answered by lynn y 3 · 0⤊ 0⤋
just distribute the (x+3)^2 into (x+3)(x+3)
y= (x^2 + 6x + 9) +1
y = x^2 + 6x + 10
2007-01-16 14:46:00 · answer #4 · answered by Bill F 6 · 0⤊ 0⤋
properly your conventional variety is incorrect... must be a(x - h)^2 + ok first of all, the a will consistently be the coefficient it is in front of the x^2 term at the instant...then set up for winding up the sq.... occasion: 5x^2 -3x + 2 => 5(x^2 - 0.6 x + ___ ) + 2 + ___ winding up the sq. could be a 0.3^2 (submit to in ideas for the 2d sparkling which you do the different sign because of the fact the interior and likewise do not forget on the subject of the greatest coefficient 5 as a effect) 5(x^2 - 0.6x + 0.9) + 2 - 4.5 => 5(x-0.3)^2 - 2.5 something are yours.
2016-10-31 07:56:14 · answer #5 · answered by gilbert 4 · 0⤊ 0⤋