The hypotenuse of a right triangle is 28 cm long and the length of one of the legs is 23 cm. Find the length of the other leg
2007-01-16 14:30:58 · 11 answers · asked by xyre_cool 1 in Science & Mathematics ➔ Mathematics
length of other leg = sqrt ( hypotenuse^2 - length of first leg^2)
= sqrt(28^2 - 23^2)
=sqrt ( 784 - 529 )
= sqrt ( 255 )
= 15.96 cm
2007-01-16 14:36:05 · answer #1 · answered by sg 2 · 0⤊ 0⤋
a² = b² + c²
28² = b² + 23²
764 = b² + 529
b² = 764 - 529
b² = 235
b = \/235
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2007-01-16 14:42:30 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
Use pythagorean theorem.
a^2+b^2=c^2, where a and b are sides, and c is the hypoteneuse.
23^2 + b^2 =28^2
b^2 = 28^2-23^2
b^2 = 255
b = 15.9687
Check:
15.9687^2 + 23^2 = 28^2
784 = 784
2007-01-16 14:37:12 · answer #3 · answered by Wolfshadow 3 · 0⤊ 0⤋
Pythagoras
28^2 = 23^2 + x^2
x = sqrt (28^2 - 23^2) = 15.96
2007-01-16 14:36:16 · answer #4 · answered by catarthur 6 · 0⤊ 0⤋
............./.l
28cm./..l
.........../...l 23cm
........../__l
formula is a^2+b^2= c^2 whereby c is the hypotenuse and a,b are the sides.
so, to find the remaining side,
a^2 + 23^2 = 28^2
after manipulation, it becomes:
a^2 = 28^2 - 23^2
so a^2 = 255
to find a to the power of one, square root it:
a = square root of 255
a = 15.97 (four significant figures / two decimal places)
2007-01-16 14:40:06 · answer #5 · answered by Gaara of the Sand 3 · 0⤊ 0⤋
So a^2 +b^2 =c^2 and the sqrt of c^2-a^2 =b or ~ 15.97 cm
2007-01-16 14:40:01 · answer #6 · answered by lynn y 3 · 0⤊ 0⤋
The answer is the square root of 255.
2007-01-16 14:36:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
a2+b2=c2
c is the hypotenuse
Now, plug in the numbers.
(remember, though, this equation only works for right triangles.)
2007-01-16 14:41:09 · answer #8 · answered by Anonymous · 0⤊ 0⤋
15.968719 cms
2007-01-16 14:45:54 · answer #9 · answered by seraj4 2 · 0⤊ 0⤋
15.968 or 16
2007-01-16 14:37:07 · answer #10 · answered by rain w 1 · 0⤊ 0⤋