Find the vertical and horizontal components of a 50N force that is directed 50 degrees above the horizontal?

Answer 1

I am not sure if you know trigonometry but sin50 = y/50. So the vertical component y = 50 * sin50. Th horizontal component would be x = 50 * cos 50. Draw a picture of a triangle with the hypotenuse of 50 at a 50 degree angle. This will help you visualize things. Prove the answer is correct by using the pythagorean theormen a^2 + b^2 = c^2