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Every 5 seconds,half of the water in a cistern empties out into a drain. If the cistern were fullto start with, what fraction of the cistern will still contain water after 25 seconds?
A 1/2 B 1/32 C 1/8 D 1/16

2007-01-16 14:13:02 · 7 answers · asked by shencock2000 1 in Science & Mathematics Mathematics

7 answers

After 1 second, you'd have 1/2 of 1, or 1/2.

After 2 seconds, you'd have 1/2 of 1/2, or 1/4.

After 3 seconds, you'd have 1/2 of 1/4, or 1/8.

After 4 seconds, you'd have 1/2 of 1/8, or 1/16.

After 5 seconds, you'd have 1/2 of 1/16, or 1/32.

(1/2)^5 = 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/32, answer B.

2007-01-16 14:16:25 · answer #1 · answered by Jim Burnell 6 · 0 0

After 5 seconds 1/2 of the water will be gone. Five seconds later half the remaining water or 1/4 of the capacity will remain. Five seconds later 1/2 the remaining water has gone and 1/8 or the tank remains. Half again in the next five seconds and we're down to 1/16. At then end of the remaining five seconds, 1/32 of the original amount will remain.

2007-01-16 22:17:48 · answer #2 · answered by Magic One 6 · 0 0

In 5 secs, it is 1/2 of the total volume of water.
So,
5 sec = 1/2
10 secs = 1/2 divided by 2
15 secs = 1/4 divided by two again
and so on, so it is (1/2)^5 because 25 secs is 5 times of it.

*1/4 because 1/2 divide by 2 = 1/2 x 1/2 = 1/4

So, the answer is 1/32 ( 1/ 2x2x2x2x2 = 1 / 32)

2007-01-16 22:21:13 · answer #3 · answered by Gaara of the Sand 3 · 0 0

1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/32

2007-01-16 22:16:52 · answer #4 · answered by John G 4 · 0 0

B....But, consider IF one half of the total water drained in 5 seconds, it would be empty in 11 seconds.

2007-01-16 22:22:51 · answer #5 · answered by Dusty 7 · 0 0

5 50%
10 25%
15 12.5%
20 6.25%
25 3.125% = 1/32

2007-01-16 22:17:42 · answer #6 · answered by Anonymous · 0 0

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2007-01-16 22:16:38 · answer #7 · answered by Crazystuff <3 1 · 0 1

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