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Is (sq rt of x)^2=x an identity (true for all nonnegative values of x)?

2007-01-16 14:12:49 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

It's true for all NON-NEGATIVE values of x, but it's not true for all x.

In fact, it's another way to define the absolute value function:

| x | = √(x²) = x if x ≥ 0, -x if x < 0

Example:

| -1 | = √((-1)²) = 1

2007-01-16 14:19:11 · answer #1 · answered by Jim Burnell 6 · 0 0

| x | = √(x²) = x if x ≥ 0, -x if x < 0

2007-01-16 14:48:43 · answer #2 · answered by Anonymous · 0 0

not at all
the sqrt(x) is NOT defined for x negative. .
so your "identity" is actually an expression that does NOT make sense for x<0 .

2007-01-16 14:52:41 · answer #3 · answered by tablecloth 1 · 1 0

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