2007-01-16 13:51:11 · 5 answers · asked by College guy 1 in Science & Mathematics ➔ Mathematics
its always continuous in the real world o.o
2007-01-16 13:58:39 · answer #1 · answered by Taras 2 · 0⤊ 0⤋
In the graph of a ratio, there will be a discontinuity where the denominator is zero.
In this case, the denominator will be zero only if xsquared = -4.
This does not happen, not for real numbers anyway. Therefore it is a continuous function.
(For complex numbers, there will be a discontinuities at x = +2i and x = -2i)
2007-01-16 21:58:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It's continuous everywhere, because x² + 4 is never 0.
This is a rational function and is continuous everywhere
except where its denominator is 0.
2007-01-16 22:06:26 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
That function is continuous for all real numbers, with discontinuties at +/- 2i
However, if the sign in the bottom was - instead of + (did you copy it right?) you'd have discontinuties at +/- 2. The one at 2 would be removable.
2007-01-16 22:06:14 · answer #4 · answered by Joni DaNerd 6 · 0⤊ 0⤋
If graphed on a real vs. imaginary plane, then at the points 2i and -2i.
2007-01-16 21:56:41 · answer #5 · answered by mjatthebeeb 3 · 0⤊ 0⤋