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Please help i gotta an E.Q.A.O thing tomorrow

2007-01-16 13:50:32 · 5 answers · asked by aamir925 1 in Education & Reference Homework Help

5 answers

you have to put it into point-slope form
y=mx+b
b is the constant, m is the slope...
so you would graph y=6x-4 by going to -4 on the y axis, and then using slope- 6, rise over run, to find another point, you need probably 3 points in order to draw a line
so you do the slope for each point, and then connect the dots.
Now there is standard form, and point- slope form.
we'll change 4x+3y=12 to slope intercept form, because you have to get to slope intercept form in order to graph- basically you just isolate the way
so you would subract 4x from 12, and it would be 3y=-4x+12
then you would divide it by 3- y= -4/3x+4
now you just follow the first thing i told you.
for point slope= it is y-y(sub1)=m(x-xsub1) (it's kind of hard to show you on this...)
so for this you already have a point- the second way, and the second x. so what you do is start at that point, then do the slope from there. make sure you read the directions because sometimes they say you need to put it into slope-intercept form before you graph.
For your textbook, there may also be online sites. These have helped me- if you have prentice hall- they have a teacher teaching it for you, so its very easy to understand. the site for that is PHschool.com
you can just search on google for you publisher of the textbook and the subject- and you should be able to find it...
hope this helps! good luck!

2007-01-16 14:01:49 · answer #1 · answered by catchingfreak51 3 · 0 0

choose values for x and substitute them into the problems and simplify and that will give you the y value for each respective x value, then plot each point and connect the dots, in the case where the equation is in standard form (4x+3y=12) then you must first solve for one of the variables then do what i said before, i find that to be the easiest way to graph lines like those

2007-01-16 14:31:04 · answer #2 · answered by the_next_big_thing22 2 · 0 0

okay. the #x is the "slope" and the other number is the y intercept. take y=6x-4 for example.

-4 is your y intercept, so start at this point: (0, -4)
6x is your slope, so virtually 6/1 is the slope.

start at (0, -4) and go up 6, over 1. its rise/run... rise 6...run 1!!!

hope that helps

2007-01-16 13:55:08 · answer #3 · answered by mwctbs 1 · 1 0

The easiest way graph these equations is to put y by itself on one side, then graph using the y = mx + b method

1. m is the slope ( + is rising, - is descending)
2. b is the y-intercept
3. draw the line

2007-01-16 13:55:33 · answer #4 · answered by candice_t24 1 · 0 0

Read this and you'll get 100% tomorrow:

http://serc.carleton.edu/quantskills/methods/quantlit/basicgraph.html

good luck!

2007-01-16 13:54:31 · answer #5 · answered by Eze 3 · 0 0

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