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I have one problem left on my review packet that I cannot figure out how to get to the answer...

The impulse applied by a mallet to a croquet ball when it is struck with 35 N force for 0.08s is 2.8 N*s...
What speed does the 0.68 kg croquet ball have just after being struck?

2007-01-16 13:45:44 · 1 answers · asked by JitterBug589 3 in Education & Reference Homework Help

1 answers

Impulse (I) = change in momentum (Δp)
I = 2.8 Ns = Δp

If the ball started at rest, then the momentum of the ball is 2.8 Ns.
So:
p = 2.8 Ns = mv = 0.68 kg * v
v = 2.8 Ns / 0.68 kg = 4.12 m/s (solution!)

2007-01-17 02:11:00 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

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