Geometry Question?

Question

If an equilateral triangle has sides of length 16, how would you find the length of an altitude?

Answer 1

You could first draw the equilateral triangle on a piece of paper,then write the sides of lenght at each side of the triangle.As the altitude of the equilateral triangle is also the bisector,the half of the side is 8.So now here is the answer:
Altitude=(16^2-8^2)^1/2=13.856

Answer 2

In an equilateral triangle ,if a perpendicular is dropped from a vertex on its opposite side it bisects the side
The perpendicular is its altitude
Thereforealtitude^2=16^2-8^2=256-64=192
therefore, Altitude=(sqrt)192 units=13.856 units

Answer 3

set up a 30-60-90 triangle by drawing in the altatude (draw this now!)

the altatude splits the top angle

across from 30 is X 60 is X rad. 3 90 is 2X

if we know that the side across from the 90 deg. angle is 12, we can set that equal to 2X. across from the 60 is X rad. three, and X=6.

the answer is 6*sq. rt. 3; which is about 10.4

Answer 4

the altitude is the hieght of the triangle
pythagorem therom, 16^2 (hypotunuse) - 8^2 (the base divided into 2) = answer.
then you squareroot that answer to get the altitude

Answer 5

im guessing a^2+b^2=c^2