Slope = -5, passing through (-4, -2)
2007-01-16 13:22:36 · 2 answers · asked by melanie m 2 in Science & Mathematics ➔ Mathematics
How do I put this into point-slope and slope-intercept forms?
2007-01-17 08:41:59 · update #1
assuming straight line graph, obviously
y = mx + c is the usual formula for a straight line, c is the point where the line cuts the y-axis, and m is the gradient
since you have m=-5, and you have a set of coordinates on the line (-4, -2), you can find out the value of c
c = y - mx = -2 - (-5 * -4) = -2 -20 = -22
hence graph formula is y = -5x -22
double check by putting the (-4, -2) coordinates into the formula:
y = (-5 * -4) - 22 = 20 - 22 = -2 (correct!)
2007-01-16 13:39:55 · answer #1 · answered by lsl4x 4 · 1⤊ 0⤋
The answer is: y=-5x+-22
The work:
y=mx+b
y=-5x+b
-2=-5(-4)+b
-2=20+b
-22=b
y=-5x+-22
Have fun grading:)
2007-01-16 13:29:01 · answer #2 · answered by ♥Super_Colts_Fan♥ 2 · 0⤊ 0⤋