Please Help w/ a physics problem?

Question

A level flight bomber aircraft, flying at a speed of 125m/s, releases a 'dumb bomb' at an altitude of 1.96x10^3 meters.

a) How far does the bomb travel horizontally between release and impact?
b) How far does the plane trave horizontally during the same time? (assume
level flight the entire time)
c) How long does it take the bomb to impact the ground from release?

Please show work
Thank You any one who takes time to attemp this

Answer 1

Let's assume that there is no air resistance -- that's the usual assumption for these problems. We're told that the aircraft is in level flight -- so there is no up/down speed. Let's assume that the bomb is dropped with zero up/down speed. The the formula we need is:
distance = (1/2) acceleration of gravity x (time of fall squared)
1960 m = (1/2) 9.806 m/s^2 x (time of fall squared)
1960 x 2 / 9.806 = (time of fall squared)
399.76 = (19.994^2)
so then, the time of fall is (about) 20.0 seconds.
That is the answer for part c.

For part b, work out how far the plane travels in 20 seconds.

For part a, it's a trick question. There's nothing to slow the bomb down horizontally (no air resistance). So then it moves 125 m/s horizontally -- the same as the airplane. The answer for part a is the same for part b.

Answer 2

The key to this is to compute the fall time of the bomb:

d=1.96 km

d=1/2*g*t^2

then use the t for the rest

using g=9.8
t=20 seconds

This is the answer to c

the bomber and the bomb will travel equal distances during the fall tinme because their horizontal speeds are equal

a and b are

d=125*t
=125*20
=2500 m

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