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A 10N sign is being held up by two strings, A and B. String A is on the left side and angled at 30 degrees and string b is on the right and is horizonta. What is the tension in string B

I need help for my exam, any ideas??

2007-01-16 12:49:06 · 3 answers · asked by Berry 1 in Science & Mathematics Physics

3 answers

I will assume the 30 degrees is downward

The vertical tension in string a is 10N, and the horizontal is equal to String B, but opposing

using trig,
sin(30)=10/A N

A=10/sin(30)

the cos(30)*A=B

so
B=10*cos(30)/sin(30)
=17.3 N

j

2007-01-16 13:23:06 · answer #1 · answered by odu83 7 · 0 0

I wish people spend a little more effort to understand the other solutions offered before rushing in to criticise them. The second answer says the same thing as the first, with a little more detail. By the way, it is the force that is shared - not the mass. I thought a school student would have known this, let alone a college physics major.
( I teach physics to college students - though that is neither here nor there.)

2007-01-16 21:56:36 · answer #2 · answered by muten 2 · 0 0

Setup a force diagram and solve for what u need!
It is all basic trig.

I don't know where this guy is from but the answer below me is so Wrong.
When u hang a mass from more than one string the mass is distributed among the strings and the amount that each one recieves is related to its angle.

2007-01-16 21:13:14 · answer #3 · answered by Michael_B_C 2 · 0 0

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