9y^3+57y^2+60y
thanks
2007-01-16 12:22:36 · 3 answers · asked by pirsimone 1 in Science & Mathematics ➔ Mathematics
First: find the least common factor - find a common variable, such as "y" > and find a number divisible by each coefficient...
3y(3y^2 + 19y + 20)
SEc: factor the expression in the parenthesis. multiply the 1st and 3rd coefficient to get 60. find two numbers that give you 60 when multiplied and 19 (2nd-middle coefficient) when added/subtracted. The numbers are 15, 4
*Rewrite the expression with the new middle coefficients-when you have 4 terms > group "like" terms & factor both sets...
(3y^2 + 15y) + (4y + 20)
3y(y + 5) + 4(y + 5)
(y + 5)(3y + 4)
Third: bring down 3y that was factored in the beginning...
3y(y + 5)(3y + 4)
2007-01-16 13:01:36 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
First try to pull out as much as you can:
9y^3 + 57y^2 + 60 y
3y(y^2+19y+20)
The factors of 20 are 1* 10 and 4 * 5, when added together, you will get 11 and 9 respectively. So this is completely factored.
2007-01-16 12:29:07 · answer #2 · answered by danjlil_43515 4 · 0⤊ 1⤋
3y(3y^2 + 19y +20 = 3y(3y+4)(y+5)
2007-01-16 12:29:58 · answer #3 · answered by davidosterberg1 6 · 1⤊ 0⤋