math question!!!?

Question

heyys. i need help on this math problem;

(x^2)^3 = 1/64

what is x? thanks!!!<33

Answer 1

*The x-variable represents a number/value that we need to find.

First: when you have one base with an expoenent raised to another exponent, multiply the exponents...

x^(2*3) = 1/64

x^6 = 1/64

Sec: eliminate the parenthesis > find the square root of both sides...

V`(x^6) = V`(1/64)

V`(x x x x x x) = V`(1)/ V`(64)

x^3 = 1/8

Third: find the cube root of both sides...

3V`(x^3) = 3V`(1/8)

3V`(x x x) = 3V`(1) / 3V`(64)

x = 1/3V`(8)
x = 1/3V`(4*2)
x = 1/3V`(2*2*2)
x = 1/2

Answer 2

(x^2)^3 = 1/64
x^6 = 1/64
Take the sixth root of each side
(Don't forget that when you take an even root, it could be positive or negative)
x = +/- sixth root (1/64)
x = 1/2 or x = -1/2

The person below me forgot that when you take a square root it could be + or -
For example, if
x^2 = 4, then x = -2 or 2.
Why is it both?
because (-2)^2 = (-2)(-2) = 4
and 2^2 = (2)(2) = 4
Both numbers, when squared, equal 4.