2007-01-16 12:00:32 · 6 answers · asked by lynn l 1 in Science & Mathematics ➔ Mathematics
Multiply 5 and -2.
(5)(-2) = -10
Now ask yourself "what factors of -10 add up to 9?"
(10)(-1) = -10 and 10 + -1 = 9
So replace 9x with 10x - x
5x^2 + 10x - x - 2
Factor by grouping
= (5x^2 + 10x) + (-x-2)
= 5x(x+2) + (-1)(x+2)
= (x+2)(5x-1)
2007-01-16 12:04:40 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
you should ask one project and then have him attempt to do others of an same type. 2. x^2 + 5x - 50 want 2 numbers which expanded get -50 yet even as further get +5 i.e. 10 * -5 = -50 and 10 - 5 = 5 so, (x +10)(x - 5) is the factored style the version between 2. & 11. is that the coefficient for x^2 in 2. is a one even as the coefficient (the quantity in the front of the variable) for 11. is a seven so, so, to component 7x^2 + 22x - 24 you want to locate aspects of seven to multiply to aspects of -24 which even as further get +22 aspects of seven are a million, 7 aspects of 24 are a million, 24 or 2, 12 or 3, 8 or 4, 6 i.e. 7*(4) = 28 and a million(-6) = -6 and 28 - 6 = 22 so, (7x - 6)(x + 4) is the factored style
2016-10-15 08:08:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5x^2 +9x -2
need two number to multiply to -10 and add to 9
10, -1
5x^2 - x + 10x - 2
=x(5x-1) +2(5x-1)
=(x+2)(5x-1)
2007-01-16 12:05:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
5x^2+ 9x - 2
(5x-1)(x+2) = 5x^2+10x-x-2 = 5x^2+9x-2
2007-01-16 12:10:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
^2 = exponent 2
5x^2+9x-2
5x -1
X
x 2
this is the x-method.
multiply diagonally. 5x * 2 =10x
-1*x=-x
10x-x=9x it makes sense.
soo/ (5x - 1)(x-2) is your answer
2007-01-16 12:07:19 · answer #5 · answered by MaggieSin 3 · 0⤊ 0⤋
(x+2)(5x-1)
Hope this helps!!
2007-01-16 12:05:05 · answer #6 · answered by Shi Yoyo 2 · 0⤊ 0⤋