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8 answers

C = 2 pi r
A = pi r^2

So when you equate these you get:
2 pi r = pi r^2

Divide both sides by pi and by r:
2 = r

So the radius of 2 will give an area of 4 pi and a circumference of 4pi.

Answer:
r = 2

2007-01-16 11:52:24 · answer #1 · answered by Puzzling 7 · 0 0

Wow, everybody so far has gotten it half right. :)

Actually everyone has the right idea, they just didn't give the "obvious" answer. So, let's follw their game plan and see what happens. You want the area numerically equal to the circumference and the value of the radius that accomplishes that. So,

pir^2 = 2pir --now rearrange
pir^2 - 2pir = 0 --now divide both sides by pi
r^2 - 2r = 0 -- now factor
r(r - 2) = 0 -- now the product is 0 whenever either of the factors (or both) are 0

r - 2 = 0 give r = 2 --which everyone got, but the other answer is when r = 0.

There are two solutions r = 2 and r = 0

HTH

Charles

2007-01-16 11:59:42 · answer #2 · answered by Charles 6 · 0 0

Good Luck

2 pi r = pi r^2

r = 2

2007-01-16 11:54:31 · answer #3 · answered by 511@ 4 · 0 0

Solve for r in r^2=2 times pi times r.
r=radius.

2007-01-16 11:54:13 · answer #4 · answered by Alex 3 · 0 0

so area of a circle (pi*r^2) = circumference of a circle (2*pi*r)
so solve pi*r^2 =2Pi*r
r^2=2r
r^2-2r =0
r(r-2)=0
r=0 or r=2
can't be 0 must be 2
check it pi*2^2=4pi
2*pi*2=4pi also

2007-01-16 11:54:51 · answer #5 · answered by dla68 4 · 0 0

2 pi r = pi r^2
cancel one r and the pi
r = 2

2007-01-16 11:52:24 · answer #6 · answered by Anonymous · 0 0

2 pi r = pi r^2

r = 2

2007-01-16 11:52:04 · answer #7 · answered by daedgewood 4 · 0 0

2pi*r=pi*r^2

r=2

2007-01-16 11:52:42 · answer #8 · answered by      7 · 0 0

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