Simplifying
(x + 3)(4x2 + 2)(x7 + -2)
Reorder the terms:
(3 + x)(4x2 + 2)(x7 + -2)
Reorder the terms:
(3 + x)(2 + 4x2)(x7 + -2)
Reorder the terms:
(3 + x)(2 + 4x2)(-2 + x7)
Multiply (3 + x) * (2 + 4x2)
(3(2 + 4x2) + x(2 + 4x2))(-2 + x7)
((2 * 3 + 4x2 * 3) + x(2 + 4x2))(-2 + x7)
((6 + 12x2) + x(2 + 4x2))(-2 + x7)
(6 + 12x2 + (2 * x + 4x2 * x))(-2 + x7)
(6 + 12x2 + (2x + 4x3))(-2 + x7)
Reorder the terms:
(6 + 2x + 12x2 + 4x3)(-2 + x7)
(6 + 2x + 12x2 + 4x3)(-2 + x7)
Multiply (6 + 2x + 12x2 + 4x3) * (-2 + x7)
(6(-2 + x7) + 2x * (-2 + x7) + 12x2 * (-2 + x7) + 4x3 * (-2 + x7))
((-2 * 6 + x7 * 6) + 2x * (-2 + x7) + 12x2 * (-2 + x7) + 4x3 * (-2 + x7))
((-12 + 6x7) + 2x * (-2 + x7) + 12x2 * (-2 + x7) + 4x3 * (-2 + x7))
(-12 + 6x7 + (-2 * 2x + x7 * 2x) + 12x2 * (-2 + x7) + 4x3 * (-2 + x7))
(-12 + 6x7 + (-4x + 2x8) + 12x2 * (-2 + x7) + 4x3 * (-2 + x7))
(-12 + 6x7 + -4x + 2x8 + (-2 * 12x2 + x7 * 12x2) + 4x3 * (-2 + x7))
(-12 + 6x7 + -4x + 2x8 + (-24x2 + 12x9) + 4x3 * (-2 + x7))
(-12 + 6x7 + -4x + 2x8 + -24x2 + 12x9 + (-2 * 4x3 + x7 * 4x3))
(-12 + 6x7 + -4x + 2x8 + -24x2 + 12x9 + (-8x3 + 4x10))
Reorder the terms:
(-12 + -4x + -24x2 + -8x3 + 6x7 + 2x8 + 12x9 + 4x10)
(-12 + -4x + -24x2 + -8x3 + 6x7 + 2x8 + 12x9 + 4x10)
2007-01-16 11:46:13
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answer #1
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answered by love e 1
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First use FOIL to multiply (x+3) (x^7-2). This gives you the result: x^8 +3x^7 -2x -6.
Take a deep breath and plunge in again.
Multiply that times 4x^2 +2.
The first round of multiplication (where you multiply 4x^2 times the expression x^8.... gives you the following result:
4x^10 +12x^9 -8x^3 -24x^2
You still need to mulitply the x^8... expression by +2, though, so you do that and you get the following result:
2x^8 +6x^7 -4x -12
Combining all of the above products into one result is not hard since they are all unique terms - there are no like terms to combine. In order, from the highest power to lowest, the answer is:
4x^10 +12x^9 +2x^8 +6x^7 -8x^3 -24x^2 -4x -12
Check it all out to make sure the results are right and in order. Don't leave out terms.
2007-01-16 12:02:32
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answer #2
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answered by kathyw 7
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let's do the first 2 brackets first usign distribution:
(x+3)(4x^2+2)= (4x^3+2x + 12x^2 +6)
mulitply this by the last bracket
remember to add the powers when you distribute
(x^7-2) (4x^3+2x + 12x^2 +6)= ( 4x^10 +2x^8 +12x^9 +6x^6
-8x^3 - 4x -24x^2 - 12)
I would then put the answer in decreasing powers to complete the question
2007-01-16 11:53:06
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answer #3
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answered by a c 7
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Definitly 7
2007-01-16 11:40:16
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answer #4
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answered by Sho'nuff 3
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Richard Simmons and Rosie O'Donnel (and no recording equipment of any form!) There are also those mixtures,... An Auctioneer and a Pimp An Ambulance driving force and a criminal professional A Trick-O-Treater and a Jahova Witness
2016-11-24 22:04:39
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answer #5
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answered by Anonymous
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(x+3)(4x^2+2)--> You must FOIL (or distribute).
(4x^3+12x^2+2x+6)(x^7-2)--> You must distribute.
x^7(4x^3+12x^2+2x+6)-2(4x^3 + 12x^2+2x+6)-->Multiple Into the terms.
4x^10+12x^9+2x^7+6x^7-9x^3 - 24x^2-4x-12-->Normally you would combine like terms however there are none, SO:
4x^10+12x^9+2x^7 + 6x^7-9x^3-24x^2-4x-12
2007-01-16 11:43:08
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answer #6
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answered by Sandman 2
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55
2007-01-16 11:40:37
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answer #7
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answered by Someone 1
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(x+3) (4x ^7-2) = fish
2007-01-16 11:41:17
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answer #8
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answered by *♥*sassymints*♥* 1
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(x+3)(4x^2+2)(x^7-2)
= 2(x+3)(2x^2+1)(x^7-2)
That's it !!
2007-01-16 11:48:58
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answer #9
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answered by ironduke8159 7
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7 lucky number
2007-01-16 11:39:47
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answer #10
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answered by pinoy_jdf 1
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