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How do you find the area of a "x" sided figure??? is there a formula???

2007-01-16 11:17:46 · 11 answers · asked by Travis L 1 in Science & Mathematics Mathematics

o and btw... if you happen to know the formula for using the circumference of a circle to find the radius of the circle, please tell me that as well.

2007-01-16 11:23:29 · update #1

how would you find the area of a hexagon???

2007-01-16 11:25:20 · update #2

11 answers

For a regular polygon area = (½)(apothem)(perimeter)

The apothem is the radius to the center of one of the sides.

2007-01-16 11:24:17 · answer #1 · answered by Barkley Hound 7 · 0 0

well for triangles and four sided figures, that is easy. Just use the formulas 1/2bh and length times base.
For other multi sided shapes, you use the formula 1/2 A P
P is the perimeter of the shape. A is the apothem. This is the line that goes from the center of that shape to one of the sides perpendicularly. To find it, just divide the shape into equal triangles (same number as sides) and draw the height of that triangle. That is the apothem

2007-01-16 11:25:19 · answer #2 · answered by Sam L 2 · 0 0

There is a formula if all the sides are equal and the object can be divided into triangles of the same size. Then:

area = perimeter * apothem / 2

The apothem will be the height of one of the triangles.

The perimeter will be the sum of all the sides or x times the length of one side.

Otherwise, try to divide your object into rectangles or triangles with known sides, calculate the area of each one and add all up.

2007-01-16 11:27:01 · answer #3 · answered by Allabor 3 · 0 0

Simple if you know how. As the number of sides increases, the polygon shape slowly becomes closer to a circle. The formula is:

Area of a regular polygon = (1/2) N sin(360°/N) * (Radius squared)

This site explains it really well...

http://www.math.com/tables/geometry/polygons.htm

2007-01-16 11:27:09 · answer #4 · answered by hardhouse_boy 2 · 0 0

I assume you mean that there could be x number of sides. I don't believe there is any one formula that would work in all cases.

2007-01-16 11:23:00 · answer #5 · answered by cottagstan 5 · 0 0

If it is a regular polygon with n sides and each side has length s, use this formula.

Area = (1/4)ns² cot(π/n)

2007-01-16 13:52:27 · answer #6 · answered by Northstar 7 · 0 0

if it's regular, just multiply the area of a side by n. if it's not, sum the areas of all the sides (not necessarily easy, but that's what "area of a figure" really means)

2007-01-16 11:22:14 · answer #7 · answered by John D 3 · 0 1

circumference: 2*pi*r

pi=3.14159.....

all you can really do is if it is a regular figure, then, the formula is height times apothem.

2007-01-16 11:26:39 · answer #8 · answered by chococat 4 · 0 0

you're duplicating some code that doesn't favor to be duplicated. indexed right here are some fixes on your code. a million. on your triangle.h record your perimeter function on the bottom desires to be declared a member function of your triangle classification. you presently have: int perimeter(int side1 ,int side2 , int side3) { int perimeter; perimeter = side1 + side2 + side3; go back perimeter; } and it desires to get replaced to int triangle::perimeter(int side1 ,int side2 , int side3) { int perimeter; perimeter = side1 + side2 + side3; go back perimeter; } 2. on your major record you've 2 function prototypes that are unnecessary, get rid of ideal right here 2 strains from the great of the code: drift section(drift,drift); int perimeter(int ,int ,int ); it truly is because those are already applications of your classification, even as holding them right here tries to lead them to into seperate applications of their own. each little thing promptly below your //declare variables remark is senseless. you've all of this knowledge already saved on your classification, there is no aspect in holding new integers and floats to save a similar files. the position you presently have // int perimeter = perimeter(side1, side2, side3); // drift section = section(top, base); you could get rid of this. it truly is commented, yet inspite of if it wasn't, it truly is unnecessary. the position you've your cout statements on the bottom, you could substitute those to call on the tri gadgets member applications like follows. cout << "The Triangle's perimeter is : " << tri.perimeter << "n"; cout << "The Triangle's section is : " << tri.section << "n";

2016-11-24 22:02:33 · answer #9 · answered by wintle 4 · 0 0

Take n to the x power...Like if the figure is an octagon, then it'd be n to the 8th power. nxnxnxnxnxnxnxn

2007-01-16 11:24:34 · answer #10 · answered by Sarah O 2 · 0 1

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