10 points
2007-01-16 10:47:45 · 6 answers · asked by grim reaper 2 in Science & Mathematics ➔ Mathematics
Subtract 48 from both sides:
x^2-13x-48=0
(x+3)(x-16)=0
x=-3 and 16
2007-01-16 10:55:21 · answer #1 · answered by Anonymous · 4⤊ 0⤋
x^2 - 13x - 48 = 0
(x - 16)(x + 3) = 0
x = 16 or x = -3
2007-01-16 18:53:43 · answer #2 · answered by Johnny Handsome 2 · 3⤊ 0⤋
x^2 - 13x -48
(x-16)(x+3)=0
x-16=0 x+3=0
x = 16 and x = -3
2007-01-16 18:51:39 · answer #3 · answered by Bill F 6 · 3⤊ 0⤋
x^2 -13X -48 = 0
ax^2 +bx+c = 0
find 2 numbers that its sum is b and multipication is a*c
the numbers are -3 and 16
16 + (-3) = -13 = b
16 * (-3) = -48 = c
so the equation can be written as :
(x-16)(x+3) = 0
which means that the solutins are 16 and -3
2007-01-16 19:01:12 · answer #4 · answered by really? 2 · 3⤊ 0⤋
move everything over to one side:
x²-13x-48 = 0
then factor:
(x-16)(x+3) = 0
set each factor equal to 0
2007-01-16 18:52:56 · answer #5 · answered by Master of All He Surveys 2 · 3⤊ 0⤋
16 and -3
2007-01-16 18:52:32 · answer #6 · answered by MeMe 1 · 3⤊ 0⤋