solve 4 X, 4X^2+5X+1=0?

3 ⤊

10 points

2007-01-16 10:44:55 · 5 answers · asked by grim reaper 2 in Science & Mathematics ➔ Mathematics

assuming that says solve for x -
you factor it to (4x+1)(x+1)=0
4x+1=0 x+1=0
4x=-1 x=-1
x=-1/4

so x = -1 and x - -1/4

2007-01-16 10:49:42 · answer #1 · answered by Bill F 6 · 1⤊ 0⤋

(4x+1)(x+1) = 0

x = to either -1 or -(1/4)

2007-01-16 18:48:30 · answer #2 · answered by Vic 2 · 1⤊ 0⤋

(4x+1)(x+1)=0
x+1=0
4x+1=0
x=-1 and -1/4

2007-01-16 18:58:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋

what the hell.... that is soo freakin hard.....sry but i suck at math

2007-01-16 18:47:29 · answer #4 · answered by lexi(: 3 · 0⤊ 1⤋

-0.25 or -1
both work

2007-01-16 18:49:54 · answer #5 · answered by MeMe 1 · 1⤊ 0⤋