This is my idea for a WWE storyline.
HBK takes some time off and leaves Flair and Cena to be DX. These two start clicking and start believing that they r truly DX. Then when HHH and HBK come back Cena and Flair refuse to recognize the original DX as DX and they claim they r DX. This starts a whole fued between DX and fake DX leading to a long battle between these two w/ original DX winning
2007-01-16 10:29:18 · 14 answers · asked by Anonymous in Sports ➔ Wrestling
that would be COOL!!!
Can i have the 10 points?????
PLEASE
2007-01-16 10:44:22 · answer #1 · answered by The answer man in Pa 2 · 0⤊ 3⤋
LOL it would be funny seeing cena and flair together as heels. Anyway it would be OK but flair and cena aint no DX
2007-01-16 18:31:18 · answer #2 · answered by Matt: aka; Edge is world champ!! 6 · 0⤊ 0⤋
you must have some good imagination but this story line isn't the best
cena is in a feud with umaga and wont really want to be part of dx. id like that idea but shawn michales is going no where.
2007-01-16 18:47:34 · answer #3 · answered by Anonymous · 0⤊ 2⤋
its not good b/c id think cena could be a bad guy he tries to act to nice flair would work though
2007-01-16 18:51:12 · answer #4 · answered by austinfsk 2 · 0⤊ 2⤋
yes its funny and exciting exspecially when cena comes out. hed da man
2007-01-16 19:24:13 · answer #5 · answered by Anonymous · 1⤊ 1⤋
Can you explain for DX, HBK & HHH means?
2007-01-16 18:31:58 · answer #6 · answered by Radio Flyer 3 · 0⤊ 4⤋
four heels in a rivalry, they r my 4 faves, seeing any one of them go heel would suck
2007-01-16 19:48:26 · answer #7 · answered by ndfreak1110 2 · 0⤊ 1⤋
thats would be funny..cena with ric?..ohhh man u must be kidding
2007-01-16 18:46:23 · answer #8 · answered by Anonymous · 0⤊ 2⤋
Are you serious. I'm totally confused.
2007-01-16 18:32:42 · answer #9 · answered by Anonymous · 0⤊ 3⤋
ya, y not. it sounds dangerous.
2007-01-16 18:31:58 · answer #10 · answered by Anonymous · 0⤊ 0⤋
I wouldn't be interested. WWE is fake.
2007-01-16 18:31:31 · answer #11 · answered by mag48 3 · 0⤊ 4⤋