English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

3 answers

|x| < -5

This has no solution because the absolute value of x is always greater than or equal to zero (that is, it is never negative).

2007-01-16 10:13:36 · answer #1 · answered by MsMath 7 · 2 0

|x|<0
|x^2+x +14|<0
In short:
|f(x)|<0
Another example can be:
|(x+y)^2|<|x^2|+|y^2|

2007-01-16 18:29:16 · answer #2 · answered by Anonymous · 0 0

|x| < -82

2007-01-16 18:13:36 · answer #3 · answered by Dee 6 · 0 0

fedest.com, questions and answers