A hip left halifax, for jamaica at 15km/h. 1 hour later, a second ship left halifax at 25km/h. After how long did the 2nd ship over take the 1st?
2007-01-16 09:42:30 · 4 answers · asked by Cutie 4 in Science & Mathematics ➔ Mathematics
The distance between the two ships when the second ship starts is 15 km, and the catching speed is (25-15) = 10 km/h.
time = distance/speed
15/10 = 1.5 hours
2007-01-16 09:46:46 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
set up two equations
ship 1 >> D=15T
ship 2 >> D=25(T-1)
D=Distance
T=Time
set the equations equal to each other
15T=25(T-1) >> Simplify
15T=25T-25 >> get like terms on one side
-10T=-25 >> divide both sides by -10
T=25/10=2.5 Hours from the time ship 1 leaves or 1.5 Hours from the time ship 2 leaves
2007-01-16 17:50:10 · answer #2 · answered by louis504842 2 · 0⤊ 0⤋
speed = distance/time
hence distance=speed*time
distance 1= distance 2 so 15*time1=25*time 2 and you know time1=time 2+1hour
so 15*(time2+1)=25*time2 => time 2=15/10=1.5h
It will take the second ship 1.5h
2007-01-16 17:50:17 · answer #3 · answered by iron_pennywise 1 · 0⤊ 0⤋
ur like a dumb nut if yooh cant answer that the answer is 15
2007-01-16 17:51:16 · answer #4 · answered by jackiee.BBy. 1 · 0⤊ 0⤋