2007-01-16 09:11:03 · 4 answers · asked by thedougman44 1 in Science & Mathematics ➔ Mathematics
First: factor the equation > find a number divisible by the coefficients which is, 6...
Sec: factor the 6 out and multiply it by the missing terms to get the original equation (6x^2-12)...
6(x^2 - 2) = 0
Third: set the expression in the parenthesis to equal "0" in order to solve for "x"
x^2 - 2 = 0
*Add 2 to both sides...
x^2 - 2 + 2 = 0 + 2
x^2 = 2
*Eliminate the exponent > find the square root of both sides...
V`(x^2) = +/- V`2
x = V`2, - V`2
2007-01-16 09:18:20 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
6x^2 - 12 = 0
6x^2 = 12
x^2 = 2
x = square root of 2
2007-01-16 17:16:59 · answer #2 · answered by JasonM 7 · 1⤊ 0⤋
add 12 to both sides >> 6x^2=12
divide both sides by 6 >> x^2=2
take the square root of both sides >> x=+SQRT of 2 or -SQRT of 2
2007-01-16 17:41:02 · answer #3 · answered by louis504842 2 · 0⤊ 0⤋
factor it out the 6:
6(x^2-2)=0
so the answer is + or - the square root of 2
2007-01-16 17:18:10 · answer #4 · answered by Anonymous · 1⤊ 0⤋