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2007-01-16 09:09:30 · 9 answers · asked by Anonymous in Pregnancy & Parenting ➔ Pregnancy
If you know when you had your last period, count 14 days from the LAST DAY you had your period. This is the day that you are receptive and could get pregnant. Only thing is that sperm can live in your body for five days. So if the condom broke between 9 and 14 days past the last day of your last period, you are probably pregnant. If not -no worries.
2007-01-16 09:27:49 · answer #1 · answered by SpizWheel 2 · 0⤊ 0⤋
Get some birth control. It's better to have a worry free mind :) COndom's are affective but it depends on the brand. Cheaper ones are more likely to be defective. Trojan with spermicide are your best bet
2007-01-16 17:18:35 · answer #2 · answered by Chick-a-Dee 5 · 0⤊ 0⤋
if you are using the condem correctly, and it never broke so far, then you really dont have a chance of pregnancy. but always be careful because even with a condem, theres a chance, just a very low one.
you dont have anything to worry about
2007-01-16 17:15:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I would not be worried, but go on birth control in addition if you want to be safe. Pill, shot, lots of choices. Ask your dr or go to Planned Parenthood. safe and confidential. Use a condom with spermacide!
2007-01-16 17:32:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋
agree! You should be on a birth control menthod that's a little more fool proof then condoms. I recommend the Nuvaring.
2007-01-16 17:14:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋
yes. condom are not always effective. Use something else besides condoms and remember the pull out method doesn't work
2007-01-16 17:17:32 · answer #6 · answered by SuperSoldierGIJOE 3 · 1⤊ 0⤋
Next time, before you use a condom check the label for the effectiveness.
2007-01-16 17:13:57 · answer #7 · answered by hunny_b07 2 · 1⤊ 1⤋
use birth controll if being worried is an issue for you.
2007-01-16 17:13:11 · answer #8 · answered by Sassy 3 · 1⤊ 0⤋
no
2007-01-16 17:33:39 · answer #9 · answered by tinaguhc 3 · 0⤊ 0⤋