The cost for a long-distance telephone call is $0.36 for the
first minute and $0.21 for each additional minute or portion thereof. Write an
inequality representing the number of minutes a person could talk without
exceeding $3.
2007-01-16 08:43:17 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
first minute costs 0.36$
next minutes: 0.21$
assume x=number of minutes after the first minute
0.36+0.21*x=3, so x=12.6 minutes
Now don't forget the first minute, so the number of minutes you can talk without exceeding $3 is 13.6, or 13 if you need a rounded number
2007-01-16 08:49:55 · answer #1 · answered by iron_pennywise 1 · 0⤊ 0⤋
.21x + .36 < or = to 3.00
where x is the number of minutes minus 1 (the first minute cost .36 cents...) so x + 1 is the actual number of minutes
2007-01-16 16:48:54 · answer #2 · answered by Rockit 5 · 0⤊ 0⤋
x=minutes
.36 times .21x is less than or equal to 3
2007-01-16 16:47:38 · answer #3 · answered by BydaBay 4 · 0⤊ 0⤋
$.36 + $.21x(less than or equal to) $3
2007-01-16 16:47:41 · answer #4 · answered by iwantmymtv35 2 · 0⤊ 0⤋
$0.36 + $0.21x number of mins < $3.00
$3.00 - $0.36 > $0.21 x mins
mins < ($3.00 - $0.36)/$0.21
2007-01-16 16:49:28 · answer #5 · answered by lenpol7 7 · 0⤊ 0⤋