Michael Jordan was known for his "hang time," which is the amount of time a player is in the air when making a jump toward the basket. An equation that approximates that height s, in inches, of one of Jordan's jumps is given by s=-16t+26.6t, where t is time in seconds. Use this equation to determine Michael Jordan's hang time, to the nearest tenth of a second, for this jump.
Can some one plz help me with this question. I tried everything I can't seemed to figure it out. So can you plz give me an example of how to solve this problem. I do not want the answer because I have this weird issue with feeling guilty for writing down someone else's work. So if you can just give me an example or break it down for me a little bit it would help me alot. Thanxs..
2007-01-16 08:36:37 · 3 answers · asked by Precious Angel 2 in Science & Mathematics ➔ Mathematics
the equations is s=16t^2+26.6t
2007-01-16 08:51:20 · update #1
If the question is correctly written, then first simplify the equation.
s = -16t + 26.6t becomes
s = 10.6t, then to find the "hang time" isolate t (time)
s/10.6 = 10.6t/10.6, which becomes
s/10.6 = t
So, to find "hang time", divide the height of the jump by 10.6.
2007-01-16 08:45:01 · answer #1 · answered by Rockit 5 · 0⤊ 0⤋
The equation for s probably should have a power of 2 in it. (-16t^2+26.6t). Functions with a power of 2 will be parabolas. You need to solve for t when s=0 because these are the times when MJ is leaving the ground and lands on the ground. These solutions for t when s=0 can be done on paper or by graphing the equation and seeing the two points it crosses the x-axis.
2007-01-16 16:44:06 · answer #2 · answered by mxdude34 1 · 0⤊ 0⤋
s = -16t +26.6t
Factorise 't' :-
s = t(-16 + 26.6)
s = t(10.6)
t = s/10.6
So the 'hang time' would be, say for a 10 inch jump,
t = 10/10.6 = 0.94339 seconds.
2007-01-16 16:45:54 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋