what is x^3-8?

Answer 1

Factor using difference of cubes rule.
x^3 - 8 is actually x^3-2^3, since 2^3 is 8

RULE: x^3 - y^3 = (x-y)(x^2 + xy + y^2)

x^3-2^3
=(x-2)(x^2+2x+2^2)
(x-2)(x^2+2x+4)

Answer 2

This means you substitute in different values for 'x'. Cube those values , that multiply itself three times over ( eg 2 x 2 x 2 = 2^3)
Then you subtract 8 from the answer.

Answer 3

*You need to know the difference of cubes formula >>>
>> (a - b)(a^2 + ab + b^2)

First: break down the expression - eliminate the exponent beside the "x" ...

(x)(x)(x) - (2)(2)(2)

*You need a term for the "a" and "b" variable: a = x and b = 2

Sec: replace "x" with the a-variable and replace "2" with the
b-variable in the formula....

(x - 2)(x^2 + x(2) + 2^2)

(x - 2)(x^2 + 2x + 4)

Answer 4

To solve for x.Consider x^3-8 equals 0
x^3-8=0
x^3=8
x=2

If you want to find what is x^3-8 you must know x.

Answer 5

That's a binomial expression in x of degree three.
What do you want to do with it?
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