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Explain what happens when one bulb burns out in a circuit made up of six bulbs connected in series with one another?

2007-01-16 08:05:57 · 7 answers · asked by ♫ Saaskie ♫ 1 in Science & Mathematics Physics

7 answers

Christmas lights are a series circuit. Pull one and they all go out. in a series circuit the current is equal everywhere, not the voltage as in a parallel circuit...

2007-01-16 08:17:50 · answer #1 · answered by Beach_Bum 4 · 1 0

Since the circuit is interrupted, there is no reason for the current to travel through the circuit. Therefore all 6 of the light bulbs go out. This is why often lights are wired in parallel.

2007-01-16 08:15:33 · answer #2 · answered by Blueearth423 2 · 1 0

it depends on the circuit being used.....if it is on a sequence circuit (1=2=3=4=5) if any of the bulbs go out they all will but if it is on a parallel circuit they are all wired to the power supply separately

2007-01-16 09:10:26 · answer #3 · answered by Anonymous · 0 0

All of the bulbs will go out, since the circuit is now broken.

2007-01-16 08:15:11 · answer #4 · answered by Randy G 7 · 1 0

The Republican might want to have a commitee to study why the lightbulb mandatory to get replaced, the Democrat might want to have 3 communities bidding to be those to regulate the bulb, the liberals might want to assert enable's mild candles-,who desires mild bulbs!

2016-11-24 21:40:44 · answer #5 · answered by Anonymous · 0 0

The others stop too.

Unlike parallel, in series it's a chain:

START->A->B-C-D->E->F->G-END

If one of them blows, then the power can't travel through. It goes dark because it blew, and the others go dark because they can't transport the power round-trip.

Parallel is different. They all share the power, so one blowing doesn't affect the others as far as shutting them off.

2007-01-16 08:15:48 · answer #6 · answered by T J 6 · 1 0

Nothing very noticeable. The other five will still be illuminating.

2007-01-16 08:14:33 · answer #7 · answered by Afi 7 · 0 3

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