2007-01-16 07:41:14 · 7 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
35x³ - 19x² + 2x
x(35x² - 19x + 2)
x(35x² - 5x - 14x + 2)
x[5x(7x - 1) - 2(7x - 1)]
x(5x - 2)(7x - 1)
- - - - - - - -s-
2007-01-16 08:52:11 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
35x^3 - 19x^2 + 2x
Take out common factor x :
x(35x^2 - 19x + 2)
Factorise bracketed term :
x(7x - 1)(5x - 2)
2007-01-16 07:50:45 · answer #2 · answered by falzoon 7 · 0⤊ 0⤋
FIrst, factor out x, giving x(35x*2 - 19x +2). The easiest way to factor the quadratic term is to equate it to zero and solve the result by the quadratic formula; if this gives roots r1 and r2, then the factors are (x - r1)(x - r2).
2007-01-16 07:49:19 · answer #3 · answered by Anonymous · 1⤊ 0⤋
the only value these terms have in common is x... so: x(49x^2-42x+8) then you factor the trinomial... 49*8=392... you need two numbers that multiply to get 392 but add up to -42.. that will be -28 and -14 replace -42 with -28x & -14x then factor by grouping... 49x^2-28x-14x+8 7x(7x - 4) -2(7x - 4) (7x-2)(7x - 4).. don't fprget we factored out x in the beginning so the final answer is... x(7x - 2)(7x - 4)
2016-05-25 02:32:09 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Factor out an x:
x(35x^2-19x+2)
Now, you can factor it:
x(7x-1)(5x-2)
2007-01-16 07:50:35 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x(35x^2 - 19x + 2) = x(7x - 1 )(5x - 2)
2007-01-16 07:48:28 · answer #6 · answered by S. B. 6 · 1⤊ 0⤋
I don't even understand the question.
2007-01-16 07:47:04 · answer #7 · answered by gabnella 6 · 1⤊ 1⤋