n=4 is a counter-example because 2(4)+1 = 9, which is not a prime.
2007-01-16 07:38:56
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answer #1
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answered by sahsjing 7
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4. n=4, 2 x 4 = 8 + 1 = 9, 9 is not a prime number.
2007-01-16 07:39:23
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answer #2
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answered by Anonymous
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n=4, 2(n)+1=9
2007-01-19 04:31:29
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answer #3
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answered by shaena j. hillier 1
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1. n = 1, 2n + 1 = 3, 3 is prime
2. n = 2, 2n + 1 = 5, 5 is prime
3. n = 3, 2n + 1 = 7, 7 is prime
4. n = 4, 2n + 1 = 9, 9 is NOT prime
2007-01-16 07:39:53
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answer #4
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answered by Dave 6
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4 since 9 is not a prime number
2007-01-16 07:41:42
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answer #5
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answered by wally 3
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4. n=4 (since this gives the result 9 when using 2n + 1, which is not a prime no. n=1,2,3 gives the answers 3,5,7 (respectively), all of which are prime no's)
2007-01-16 08:00:59
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answer #6
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answered by devilspixie 2
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n=4, since 2*4+1 = 9 = 3^2, which is not prime.
The other choices give 3,5,7 which are all prime.
2007-01-16 07:45:41
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answer #7
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answered by steiner1745 7
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Not quite, If I understand you correctly. Assume that p1, p2, ........., pn are the only primes where p1 < p2 < .... < pn Suppose Q = p1 * p2 * ..... * pn +1 Since none of the pk (1<= i <= n) can divide Q (pk divides Q - 1 => pk cannot divide Q), we conclude that either Q is a prime greater than pn or Q is a composite integer divisible by a prime greater than pn Either conclusion implies that the original assumption that there are a finite number of primes is false
2016-05-25 02:21:38
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answer #8
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answered by ? 4
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By trying each case, you see that of the list of (2n+1):
1. 3
2. 5
3. 7
4. 9,
9 is not prime.
2007-01-16 07:39:30
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answer #9
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answered by math grad student 1
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4 Silly
2007-01-16 07:41:30
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answer #10
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answered by fly5tang 1
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