2007-01-16 06:57:22 · 14 answers · asked by texas_diamond_diva 1 in Science & Mathematics ➔ Mathematics
4(x-3) -2(x-1) > 0
4x-12 - 2x+2 > 0
2x -10 >0
2x > 10
x>5
2007-01-16 07:01:04 · answer #1 · answered by john smith 4 · 2⤊ 1⤋
4(x - 3) - 2(x - 1) > 0
First: eliminate parenthesis > multiply the outer terms with the terms in the parenthesis...
4(x) - 4(3) - 2(x) - 2(-1) > 0
4x - 12 - 2x + 2 > 0
Sec: combine "like" terms....
4x - 2x - 12 + 2 > 0
2x - 10 > 0
Third: add 10 to both sides (moving varibles to the opposite side means: use the opposite sign)...
2x - 10 + 10 > 0 + 10
2x > 10
*Solve for "x" by isolating it on one side > divide both sides by 2...
2x/2 > 10/2
x > 5
P.S. Some of you should be nice to others, instead of accusing someone of cheating. Some people don't understand certain math problems-were here to help.
2007-01-16 07:45:04 · answer #2 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
Open all the brackets 4x^2 + 4x + 1 -6x -3 -8x^2 +2 =0 Collect like terms together -4x^2 - 2x = 0 This is the sames as 4x^2 + 2x = 0 factorize with 2x Gives 2x(2x +1) = 0 So x = 0 or -1/2
2016-05-25 01:58:59 · answer #3 · answered by ? 4 · 0⤊ 0⤋
4x - 12 - 2x + 2 > 0
2x - 10 > 0
2x > 10
x > 5
2007-01-16 07:03:13 · answer #4 · answered by The Annoying Thing 2 · 3⤊ 0⤋
4(x - 3) - 2(x - 1) > 0
4x -12 -2x +2 >0
2x -10 > 0
2x > 10
x > 5
2007-01-16 07:01:39 · answer #5 · answered by DT 4 · 3⤊ 1⤋
4(x - 3) - 2(x - 1) > 0
4x - 12 - (2x - 2) > 0
4x - 12 - 2x + 2 > 0
2x - 10 > 0
2x - 10 + 10 > 0 + 10
2x > 10
2x/2 > 10/2
x > 5
- - - - - - - s-
2007-01-16 07:57:21 · answer #6 · answered by SAMUEL D 7 · 1⤊ 0⤋
4(x - 3) - 2(x - 1) > 0
4x - 12 - 2x + 2 > 0
2x - 10 > 0
2x > 10
x > 5
2007-01-16 07:01:36 · answer #7 · answered by Tom :: Athier than Thou 6 · 2⤊ 2⤋
4x-2x-12+2>0
2x>10
x>5
2007-01-16 07:05:20 · answer #8 · answered by Zidane 3 · 2⤊ 0⤋
4x-12-2x+2>0
2x-10>0
2x-10+10>0+10
2x>10
x>5
2007-01-16 07:15:07 · answer #9 · answered by Dave aka Spider Monkey 7 · 3⤊ 0⤋
Use distributive property:
4x-12-2x+2>0
Combine like terms:
2x-10>0
Add 10 from both sides:
2x>10
Divide 2 from both sides:
x>5
2007-01-16 07:35:29 · answer #10 · answered by Anonymous · 2⤊ 0⤋