2007-01-16 06:57:04 · 7 answers · asked by texas_diamond_diva 1 in Science & Mathematics ➔ Mathematics
7x + 1 < 4(x - 2)
7x + 1 < 4x - 8
7x + 1 - 4x < 4x - 8 - 4x
3x + 1 < - 8
3x + 1 - 1 < - 8 - 1
3x < - 9
3x / 3 < - 9 / 3
x < - 3
- - - - - - - s-
2007-01-16 08:01:59 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
First: eliminate parenthesis > multiply the outer term with the terms in the parenthesis...
7x + 1 < 4(x) - 4(2)
7x + 1 < 4x - 8
Sec: combine "like" terms > subtract 1 from both sides...
7x + 1 - 1 < 4x - 8 - 1
7x < 4x - 9
*Subtract 4x from both sides...
7x - 4x < 4x - 4x - 9
3x < - 9
Third: isolate "x" on one side > divide both sides by 3...
3x/3 < - 9/3
x < - 3
2007-01-16 08:11:36 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
7x+1<4(x-2)
7x+1<4x-8 distribute
7x<4x-9 subtract 1 from both sides
3x<-9 subtract 4x from both sides
x<-3 divide both sides by 3
2007-01-16 07:06:34 · answer #3 · answered by d.treadway 2 · 1⤊ 0⤋
7x + 1 < 4(x - 2)
7x + 1 < 4x - 8
3x < -9
x < -3
2007-01-16 07:04:35 · answer #4 · answered by Tom :: Athier than Thou 6 · 1⤊ 0⤋
the solution is:
7x+1 < 4x - 8
3x <-9
x<-3
2007-01-16 07:05:22 · answer #5 · answered by HIMANSHU A 1 · 1⤊ 0⤋
h^2+10h=-21 +21 h^2+10h+21=0 (h+7 ) ( h+3 ) h+7=0 h+3=0 h=-7 h=-3 -------------------- 2x^2-7x-9=0 (2x -9 ) (x +a million ) 2x-9=0 x=-a million 2x=9 x=9/2 -------------------- 3m^2-5m=-2 3m^2-5m+2=0 (3m- 2 ) (m-a million) m=2/3 m=a million its perplexing to describe the for this reason of do it..
2016-12-16 06:09:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋
7x+1<4x-8
7x+1-1<4x-8-1
7x<4x-4x-9
3x<-9
x<-3
2007-01-16 07:20:46 · answer #7 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋