a. B = (R - A)/x
b. B = (A - Rx)/x
c. B = (R - Ax)/x
???????????
2007-01-16 06:51:49 · 4 answers · asked by kay 1 in Science & Mathematics ➔ Mathematics
c
R = Ax + Bx
R - Ax = Bx
(R - Ax)/x = B
2007-01-16 07:01:39 · answer #1 · answered by Scythian1950 7 · 0⤊ 1⤋
the answer is C. Solve it like you would a equation with b for the variable. You first, distribute the x into the problem in the parenthesis: R=Ax+Bx. Then, you realize that Ax is positive and the to remove it is to subtract Ax and will leave with Bx on the right side of this equation (remember, what you do on one side, you must do to the other in order to keep it balanced). That means you must subtract Ax from the left side of the equation also, leaving you with: R-Ax=Bx. Now, to get that B alone, you must realize that the right hand side of the equation is a multiplication problem so the only way to remove it is to divide right? So the right hand side now is only B. REMEMBER! You must do to both sides of the equation so you must divide the left hand side of the equation by X. And you are left with R - Ax/ X. Same as (R-Ax)/x. So choice c is the correct answer.
2007-01-16 07:22:31 · answer #2 · answered by Jasmineh 2 · 0⤊ 1⤋
First: divide both sides by "x"
*Cross cancel "like" terms....
R/x = A + B
Sec: subtract "A" from both sides...
(R/x) - A = A - A + B
(R/x) - A = B
B = (R/x) - A
The choices you listed are not the solution.
2007-01-16 09:36:19 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
Answer is c. B= (R-Ax)/x
2007-01-16 07:02:32 · answer #4 · answered by HIMANSHU A 1 · 0⤊ 1⤋