2007-01-16 06:36:15 · 7 answers · asked by coe3231 1 in Science & Mathematics ➔ Mathematics
Basically you need to find the LCM (lowest common multiple) of all these digits:
1 = 1
2 = 2
3 = 3
4 = 2 x 2
5 = 5
6 = 2 x 3
7 = 7
8 = 2 x 2 x 2
9 = 3 x 3
You need 2 x 2 x 2 to cover 8
You need 3 x 3 to cover 9
You need 5 to cover 5
You need 7 to cover 7
All the rest include these digits as factors already.
So you need 2 x 2 x 2 x 3 x 3 x 5 x 7 = 2,520
(Same as 5 x 7 x 8 x 9 = 2,520)
2,520 / 1 = 2,520
2,520 / 2 = 1,260
2,520 / 3 = 840
2,520 / 4 = 630
2,520 / 5 = 504
2,520 / 6 = 420
2,520 / 7 = 360
2,520 / 8 = 315
2,520 / 9 = 280
2007-01-16 06:41:47 · answer #1 · answered by Puzzling 7 · 3⤊ 0⤋
3 x 3 x x 2 x 2 x 2 x 5 x 7 = 2520
2007-01-16 06:42:28 · answer #2 · answered by Shorty 2 · 2⤊ 0⤋
N= 8*9*5*7=2520
2007-01-16 07:05:09 · answer #3 · answered by santmann2002 7 · 1⤊ 0⤋
9 x 8 x 7 x 5 x 3 = 7560
2007-01-16 06:45:43 · answer #4 · answered by Anonymous · 0⤊ 1⤋
1*2*3*2*5*7*2*3=2520 (the smallest common multiple)
2007-01-16 07:18:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
lcm of 1,2,3,4,5,6,7,8,9 = 2520
which is the required number.
2007-01-16 06:52:05 · answer #6 · answered by HIMANSHU A 1 · 0⤊ 0⤋
4x5x7x9 because the other numbers are factors of these.
2007-01-16 06:40:29 · answer #7 · answered by JJ 7 · 0⤊ 2⤋