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The exhaust temperature of a Carnot heat engine is 330°C. What is the intake temperature if the efficiency of the engine is 27.0%?

The equation I have been using is:

efficiency = 1- (Tcold/Thot)
rearranging for:

Tcold = -Thot (efficiency-1)
Tcold = -603.15K (.27-1)
Tcold = 440.2995 K -273.15 = 167.1495* C

But I put that answer in and it says it's incorrect. Any help would be appreciated.

2007-01-16 06:30:44 · 2 answers · asked by flossie116 4 in Science & Mathematics Physics

2 answers

Your answer is okay.

Tc=167.15* C

2007-01-16 06:43:19 · answer #1 · answered by Edward 7 · 0 0

I checked you:

Carnot efficiency equation is right
conversions are right
algebra is right

If you're doing an online quiz/practice quiz the only thing I can think of is the rounding? You seem right to me. Thermo I was my least favorite class second only to Calc II, but this shouldn't be a tough one.

edit: floodtl, better check that again.

2007-01-16 14:42:48 · answer #2 · answered by Gerfried 2 · 0 0

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