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I know how to find the answer but I need to set up an equation. How do I do that?

Car rental agency A will rent a compact car for $35 per day and an additional charge of $0.24 per mile. Car rental agency B will charge only $0.16 per mile but charges $41 per day. If Adam wanted to rent a car for three days, how many miles would Adam have to drive to make car rental agency B a better bargain?

2007-01-16 06:00:56 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

Yes, But you also have to take into account the difference of rate per day price. How can I include that into my equation to come to a solution?

2007-01-16 06:09:19 · update #1

8 answers

For a certain number of miles X, the cost of the car is as follows:

Car A = 35(3)+.24X
Car B = 41(3)+.16X

Then solve the equation

105+.24X > 123+.16X

X has to be greater than 225. So Adam would have to drive more than 225 miles for car B to be a better bargain.

2007-01-16 06:06:04 · answer #1 · answered by woodysbeard 2 · 1 1

Let no. of miles to be travelled to make B a better bargain be 'x'.
Therefore, by the given condition:
Cost for travelling 'x' miles for three days along with rent for A must be greater than B.
Therefore,
35*3 +0.24*x > 41*3 +.16*x
or 105 +0.24x>123+0.16x
or 0.08x>123-105
or or x>18/0.08
or x>1800/8
or x>225
Therefore after travelling any distance more than 225 miles B will be a better bargain than A.

2007-01-16 06:36:58 · answer #2 · answered by HIMANSHU A 1 · 0 0

agency B) 3*41+0.16*m
agency A) 3*35+0.24*m


123+0.16m< 105 +0.24m===> 0.08m> 18 m> 225 miles

2007-01-16 06:14:25 · answer #3 · answered by santmann2002 7 · 0 0

( 3 * 35 ) + .24x = (3 * 41) + .16x
105 + .24x = 123 + .16x
.08x = 18
x = 18 / .08 = 225
After 225 miles is the break even point. After that, B will be cheaper.

2007-01-16 06:07:53 · answer #4 · answered by DanE 7 · 1 0

Let x = miles driven.
3*$35 + $0.24x > 3*$41 + $0.16x
$0.08x > 3*$6
x > 225 miles

2007-01-16 06:23:56 · answer #5 · answered by Helmut 7 · 0 0

35*3 + 0.24x > 41*3 + 0.16x
105 + 0.24x > 123 + 0.16x
0.08x > 18
x > 225

2007-01-16 06:07:17 · answer #6 · answered by Bayou Brigadier 3 · 1 0

well, let's say that the number of days you rent the car is x and the number of miles you drive the car is y.

then the cost from the first place would be 35x + .24y = C
and the cost from the second place would be 41x + .16y =C

2007-01-16 06:23:42 · answer #7 · answered by Zach T 2 · 0 0

m=miles
35+.24m=41+.16m
Solve for m. m+1 miles will make B a better option

2007-01-16 06:06:32 · answer #8 · answered by ENA 2 · 0 2

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