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(c-2d) (c^2 + 2cd - 3d^2)

Can't seem to figure it out, step-by-step plz.

2007-01-16 04:40:44 · 10 answers · asked by James A 1 in Science & Mathematics Mathematics

10 answers

Multiplication is relatively simple (c-2d) (c^2 + 2cd - 3d^2)

Take the c from the first bracket (c-2d) and multiply it through each term in the second bracket

c(c^2 + 2cd - 3d^2) = c^3 + 2c^2d -3cd2

Do the same for the second term within the first bracket
-2d(c^2 + 2cd - 3d^2) = -2c^2d -4cd^2 +6d^3

Notice I kept the order as c then d, makes it easier to recognize same terms for the next step

original equation
(c-2d) (c^2 + 2cd - 3d^2)

multiplied out from previous steps

c^3 + 2c^2d -3cd^2 -2c^2d -4cd^2 +6d^3

****** + 2c^2d -2c^2d cancel each other out

c^3 -3cd^2 -4cd^2 +6d^3

****** -3cd^2 -4cd^2 can be added together -7cd^2

c^3 -7cd^2 +6d^3

2007-01-16 04:59:25 · answer #1 · answered by srrl_ferroequinologist 3 · 1 0

It's not as hard as it looks. First, put you multiply the second expression entirely by the first term, so you get c^3 +2c^2d-3cd^2. Then, you multiply the whole thing again by the second term, -2d. This gives you -2c^2d-4cd^2+6d^3. Then, you add the two things together. This gives you c^3-7cd^2+6d^3. The + and - 2c^2d cancel each other out.

c^3-7cd^2+6d^3

2007-01-16 04:48:33 · answer #2 · answered by theeconomicsguy 5 · 1 0

First step, distribution.
Multiply c(c^2+2cd-3d^2) you should get c^3 +2(c)^2 d - 3c(d)^2
Then multiply -2d(c^2+2cd-3d^2) you must get -2c(d)^2 -4c(d)^2 +6(d)^3. now add them up
c^3+2c^(2) d - 3c(d)^2 - 2c(d)^2 - 4c(d)^2+ 6(d)^3 you will get
c^3 - 6c(d)^2+6(d)^3. This is the answer.

2007-01-16 04:54:06 · answer #3 · answered by ♥♪♫Priya_akki™♫♪♥ 6 · 0 0

(c-2d) (c^2 + 2cd - 3d^2)
First take c*(c^2 + 2cd -3d^2) = c^3 +2c^2d -3cd^2 <-- Part 1
Now take -2d (c^2 + 2cd -3d^2) = -2dc^2 -4cd^2+ 6d^3 <-- Part 2
Now add Part 1 and Part 2 getting:
c^3+2c^2d-3cd^2 -2dc^2-4cd^2 +6d^3
=c^3 - 7cd^2 + 6d^3

2007-01-16 04:52:10 · answer #4 · answered by ironduke8159 7 · 1 0

[c-2d][c^2+2cd-3d^2]
=c^3+2c^2d-3cd^2
-2c^2d-4cd^2+6d^3]
=c^3-7cd^2+6d^3

2007-01-16 05:04:28 · answer #5 · answered by openpsychy 6 · 0 0

c(c^2+2cd-3d^2)-
2d(c^2+2cd-3d^2)
=c^3+2c^2d-3cd^2-
2c^2d-4cd^2+6d^3
=c^3-7cd^2+6d^3

2007-01-16 04:45:13 · answer #6 · answered by raj 7 · 3 0

=c^3+2c^2d-3cd^2-2c^2d-4cd^2+6d^3
=c^3-7cd^2+6d^3

2007-01-16 04:48:36 · answer #7 · answered by phalo 1 · 1 0

c(c^2+2cd-3d^2)-2d(c^2+2cd-3d^2)
c^3+2c^2d-3cd^2-2dc^2-4cd^2-6d^3
c^3-7cd^2-6d^3

2007-01-16 04:49:16 · answer #8 · answered by Gerfried 2 · 1 0

use the foil method that you should be learning if you are in 7th or 8th grade. Never mind that, it isnt even that advanced, just multiply then simplify.

2007-01-16 04:47:55 · answer #9 · answered by rand a 5 · 0 2

c-2d*c*2+2cd-3d*2
c-2d-2c+2cd-6d
c-2c+2cd-2d-6d
c-2c+2cd-8d

2007-01-16 04:53:11 · answer #10 · answered by Anonymous · 0 0

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