2007-01-16 04:37:36 · 4 answers · asked by colorado_usa_uk 1 in Science & Mathematics ➔ Chemistry
The usual test is to add silver nitrate, AgNO3, and the solution forms a white precipitate of silver chloride. Then add ammonia (ammonium hydroxide, NH4OH), and the precipitate dissolves. Add dilute nitric acid until acid, and the precipitate reappears.
AgNO3 + Cl- ===> AgCl(s)
AgCl(s) +2NH4OH ===> Ag(NH3)2+(soluble) + Cl- + 2H2O
Ag(NH3)2+ + Cl- + 2HNO3 ===> AgCl(s) + 2NH4NO3
2007-01-16 04:46:15 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
For Chloride : If we add a few drops of acidified potassium dichromate (acidified with sulphuric acid), the test solution turns orange red due to precipitation of CrO2Cl2 .
2007-01-16 12:44:58 · answer #2 · answered by anujagraj 2 · 0⤊ 0⤋
To test for a Chloride use Silver Nitrate.
If chloride is present and immediate white precipitate is formed.
Ag+ + Cl- = AgCl(s).
2007-01-17 14:19:44 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
red? - who knows - what is the test....
2007-01-16 12:40:39 · answer #4 · answered by Dr Dave P 7 · 0⤊ 0⤋