find the gradient of the straight line with the equation 5y=3-2x?

Answer 1

Divide both sides by 5 to get:

y = -2/5 x + 3/5. This is in slope-intercept form:

y = m x + b, where m is the slope, b is the y-intercept.

Thus, m = -2/5 is the gradient.

Answer 2

to find the gradient of the straight line, simply convert your equation form into y=mx+c format.
5y=3-2x
will be converted into
y=(3/5)-(2/5)x
by making y the subject by dividing both sideds by 5, hence making the coefficient of x -2/5, so the gradient of the line of this equation will be -2/5...its a downward sloping line!

Answer 3

5y=3-2x.
This can be written as:
y=(-2/5)x+3/5.
The gradient of the line is (-2/5). Answer.

Answer 4

5y = 3 -2x
Rearrange the equation into 'straight line' form.
5y = -2x + 3
Divide through by '5'.
y = -2x/5 +3/5

The gradient of a straight line is the coefficient of 'x' which in this case is '-2/5'.

Answer 5

to findthe gradient of any linear equation... get it in the form y=mx+c where m is the gradient coefficient and c is the y intercept. so in this case it would become y=(-5/2)x+(3/5)
hence m= -5/2 i.e. the gradient is -5/2 this means that for every 5 blocks down(Negative y direction), it goes 2 blocks to the right (positive x direction) or vice versa... hence forming a diagonal kinda like a backslash...i.e. the negative gradient :)
hopethat helped

Answer 6

5/2

Answer 7

it's -2/5

Answer 8

5y = 3 - 2x
5y = -2x + 3
y = (-2/5)x + (3/5)

Gradient = (-2/5)

Answer 9

5y = -2x + 3
y = (-2/5)x + 3/5
gradient = (-2/5)

Answer 10

-2/5