The function g has defining equation g(x)=x^2-3x+2. Find (and simplify) g(5+h).?

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The function g has defining equation g(x)=x^2-3x+2. Find (and simplify) g(5+h).?

2007-01-16 03:35:01 · 3 answers · asked by haileybaby331 1 in Science & Mathematics ➔ Mathematics

3 answers

g(5 + h) = (5 + h)² - 3(5 + h) + 2
= 25 + 10h + h² - 15 - 3h + 2
= h² + 7h + 12

2007-01-16 03:38:44 · answer #1 · answered by Jim Burnell 6 · 1⤊ 0⤋

g(x)=x^2-3x+ 2
Substitute x=5+h in the above equation,
we get,

g(h+5)=(h+5)^2-3(h+5)+2
=h^2+10h+25-3h-15+2
=h^2+7h+12
=h^ 2+4h+3h+ 1 2
=h(h+ 4)+3(h+4)
=(h+4)(h+3).

2007-01-16 04:09:02 · answer #2 · answered by hirunisha 2 · 1⤊ 0⤋

g[x]=x^2-3x+ 2
g[h+5]=[h+5]^2-3[h+5]+2
=h^2+10h+25-3h-15+2
=h^2+7h+12
=h^ 2+4h+3h+ 1 2
=h[h+ 4]+3[h+4]
=[h+3][h+4]

2007-01-16 03:45:07 · answer #3 · answered by openpsychy 6 · 1⤊ 0⤋