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Addition of fractions solve 4/5+5/8+6/7+2/9=

2007-01-16 01:40:08 · 11 answers · asked by Evelyn D 1 in Science & Mathematics Mathematics

11 answers

The least common denominator is 2,520, found by multiplying 5*8*7*9. The answer to the whole question then is 2016+1575+2160+560/2520=6311/2520.

Reduced, this is 2 and 1271/2520.

2007-01-16 01:47:29 · answer #1 · answered by theeconomicsguy 5 · 0 0

you are not stupid. here are your questions and answers - 1.)160 is divisible by numbers 2, 4, 5 and 10. 2.) Prime factorization of 720 = 2 x 2 x 2 x 2 x 3 x 3 x 5 3.) Greatest common factor of 24 and 42 is 6. 4.) 18/45 reduced to the simplest form = 2/5 5.) Least common multiple of 15 and 25 = 75 6.) 2/9 + 7/9 = 9/9 = 1 7.) 11/15 + 2/3 = 11/15 + 10/15 = 21/15 = 1 6/15 = 1 2/5 8.) 8 - 6 and 3/5 = (7+1) -- (6+3/5) = (7--6) (1--3/5) = 1 2/5 9.) 3/8 x 2and3/8 = (3/8)x2 and 3/8(3/8) = 3/4 and 9/64 = 48/64 + 9/64 = 57/64 10.) 3/7 devided by 6/11 = (3/7)x(11/6) = 11/14

2016-03-29 00:01:53 · answer #2 · answered by Anonymous · 0 0

Taking the denominators as integers, the least common multiple of 5, 8, 7, and 9 are the products of each prime (from the product of primes that compose each integer) raised to the highest power.

So, 5 = 5*1; 8 = 2^3; 7 = 7*1; 9 = 3^2

The LCM (and LCD) of the problem is then (2^3)*(3^2)*(5)*(7) = 5*8*7*9 = 2520. Big number...

2007-01-16 01:47:23 · answer #3 · answered by Tim 1 · 0 0

Consider the prime factors of the denominators:

5 is prime
8 = 2*2*2
7 is prime
9 = 3*3

None of these share any factors, so just multiply them all:
5*8*7*9 = 2520

2007-01-16 01:48:57 · answer #4 · answered by ? 4 · 0 0

4/5+5/8= 57/40

6/7+2/9= 68/63

57/40+68/63= 6311/2520

therefore,2520 is the L.C.D.

2007-01-16 01:58:02 · answer #5 · answered by Anamik 1 · 0 0

90

2007-01-17 08:40:44 · answer #6 · answered by Chris B 1 · 0 0

Thus illustrating that fractions suck compared to decimals.

2007-01-16 01:49:34 · answer #7 · answered by gebobs 6 · 0 0

2520 is the common denominator

- - - - s-

2007-01-16 02:05:37 · answer #8 · answered by SAMUEL D 7 · 0 0

2520

2007-01-16 01:46:00 · answer #9 · answered by SAI S 1 · 0 0

Whom ever gave you this problem needs an enema!

2007-01-16 01:49:14 · answer #10 · answered by Dr Dave P 7 · 0 0

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