How much of electicity do I need to electrolyse 1ml of water in 1sec.?

Answer 1

2 faraday for 1 mol of water i.e.18 grams of water(since 2 electrons required per mol)
1 faraday of charge ~ 96500 Coulombs

Assuming the water to be at 4ºC,density= 1g/l = 0.001 g/ml

mass of 1 ml water = 1*0.001 = 0.001 g
mols of water (for 1 ml) = 0.001/18

For 1 ml of water you need 2*96500*0.001/18 = 96.5/9 = 10.72 C

Answer 2

For 1 mole you need 2 faradays( because two H+ evolved) of electricity i.e. 193000 C
1 mole means 18 g of water,
therefore for 1 g we need=193000/18=10722.23 C
Now, density of water is 1000 kg/m^3
or 1 kg/l
or 1g/ml
therefore 1ml means 1g of water for which we have already found as 10722.23 C
now we have to find in 1s means we have to find the current which is 10722.23 A