What's the theoretical yield of precipitate of a reaction of 0.001 moles of Pb(NO3)2 and 0.008 moles of NaI?

Question

The actual yield is 1.15 cm, and I need the maximum yield in centimeters, too. If it helps, the 0.001 moles of Pb(NO3)2 are equivalent to 2 mL, and the 0.008 moles of NaI are equivalent to 16 mL.

Please Help!

Actually I need the theoretical yield in moles..

Answer 1

Pb(NO3)2 is the limiting reagent

0.001 moles of PbI2 precipitates!(Theoretical Yield)

centimeter is the unit of length DUDE!!!!

Please add details!

if I assume cm to be centimoles that is 0.01 moles.......then something can be done

Answer 2

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Answer 3

Very little.