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Help is greatly appreciated.

2007-01-14 18:39:55 · 2 answers · asked by theweirdguy1 2 in Science & Mathematics Chemistry

2 answers

Just a slight change according to me: (all except PbI2 should be aqueous)

Pb(NO3)2 (aq) + 2NaI (aq) ===> PbI2 (s) + 2NaNO3 (aq)
___________ _______________ ______________ ___________
Ionic reaction:

Pb(2+) + 2NO3(-) + 2Na(+) + 2I- ===> PbI2 (s) + 2Na+ + 2NO3-.
Na+ and NO3- are spectator ions.

2007-01-14 18:50:40 · answer #1 · answered by Som™ 6 · 0 0

recognize your solubility regulations: All nitrates are soluble. All team I metallic salts are soluble. So, NO3- and ok+ do not type something and stay in answer. Many bromides are soluble, yet silver bromide is insoluble. So, the precipitate will be silver bromide: Ag+ (aq) + Br- (aq) --> AgBr(s) The spectator ions are those that do not type a precipitate. accordingly, they are NO3- and ok+. i desire that facilitates! P.S: heavily, recognize your solubility regulations! they are needed for issues like those.

2016-11-23 19:11:40 · answer #2 · answered by Anonymous · 0 0

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