We define temperature as a measure of the average kinetic energy of the particles that make up our sample. Kinetic energy is the energy that something has because of its movement: the faster it goes, the more kinetic energy it has.
In materials with fast particles, the atoms and molecules are just zooming around, bouncing off each other and everything else. This high energy material we call "gas" or, if it is really energetic and full of ions, "plasma".
Slow everything down and stuff sticks together. This we call a liquid. Slow it down even further, and we have a solid.
Notice that we are slowing stuff down. What is happening to our kinetic energy? It's getting lower. And the temperature? It's getting lower, too (Remember temperature and average kinetic energy are related).
Now, what is the slowest speed that anything can go? Standing still! If it goes backwards, it is still moving so it will have a speed. At the point where everything stands still, the kinetic energy will be zero, just like the speed. And the temperature will be zero, too, since the average kinetic energy of all of these now motionless particles is zero, too.
Theory states that we can get really, really close to Absolute Zero (the 0 point on the Kelvin scale), but never reach it. This has to do with all kinds of things, including the fact that you can't stop electrons from orbiting around the nucleus, etc.
2007-01-14 19:10:05
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answer #1
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answered by Stephen S 3
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The starting point is the temperature in which all matter freezes. No matter can get below 0 degrees kelvin. Freezing is 271 kelvin. Boiling is 371 kelvin.
2007-01-14 18:48:06
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answer #2
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answered by eric l 6
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Kelvin is based to absolute zero and it does not have a starting point; 0 Celsius is equal to 273 Kelvin.
2007-01-14 19:45:27
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answer #3
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answered by The little "T" 3
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Each of which the temperature scales have a fix -starting point.Otherwise it can not be measure. T = t + 273
Lord Kelvin =T ,,, t= Celsius degree
2007-01-14 18:45:02
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answer #4
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answered by Anonymous
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Huh? Kelvin most certainly does have a starting point; it's called absolute zero. 0 Celsius is equal to 273 Kelvin.
2007-01-14 18:42:25
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answer #5
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answered by dukefenton 7
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0 degrees on the Kalvin scale would absolute 0: a temperature scientists have not yet been able to achieve. 0 Kalvin is the temperature at which all molecular and atomic activity stops.
2007-01-14 18:42:21
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answer #6
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answered by crazyromo 3
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a million) quantity and temparature isn't at as quickly as inverse of another. user-friendly remark: a three hundred degree range isn't 15 circumstances bigger than a range at room temparature. 2) in accordance to Buddism, lifestyles neither exists nor disappeared, lifestyles neither created nor destroyed.. It basically alterations varieties.... there is often "lifestyles", at 30C, at 0C, at -200C... At absolute 0, you may exchange into yet another you (in keeping with possibility a frustrating stable determine). whilst temperature returns to established, which you will exchange into yet another you (in keeping with possibility a shifting determine returned). there's a gamble which you would be very equivalent to you even with the undeniable fact that it is not you. 3) in accordance to Budda, you will end questioning those inconceivable questions as they serve no sturdy to his/her soul. it is comparable as asking in spite of if hen or egg got here first, whilst did the universe initiate. Having solutions to those won't make you a greater useful guy or woman, won't make this international a greater useful non violent place. Spend your power on giving your like to all living issues.
2016-12-16 05:00:28
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answer #7
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answered by karsten 4
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I thought it did have a starting point -273.15 degrees Celsius or absolute zero(kelvin).
2007-01-14 18:44:36
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answer #8
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answered by J C 5
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It does have a starting point; that point is the temperature at which thermal motion comes to a stop, which is at -273.16 C. For convenience in measurement, other temperatures have been carefully measured, and are used for calibrating instruments.
2007-01-14 18:42:50
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answer #9
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answered by Anonymous
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